A mass m of material exists in its solid stat | vedclass

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(A) Let $m$ be the total mass of the material, $L$ be the latent heat of fusion, and $s$ be the specific heat of the liquid.In Process-$1$, the energy

Vedclass · Accepted Answer

$120$

Vedclass · Answer

(A) Let $m$ be the total mass of the material, $L$ be the latent heat of fusion, and $s$ be the specific heat of the liquid.In Process-$1$, the energy $Q$ melts $\frac{2}{3}$ of the mass:$Q = \frac{2}{3} m L$ --- (Equation $1$)In Process-$2$, an additional energy $Q$ is added. This energy first melts the remaining $\frac{1}{3}$ of the solid and then raises the temperature of the entire liquid mass $m$ from $0^\circ C$ to $40^\circ C$:$Q = \frac{1}{3} m L + m s (40 - 0)$$Q = \frac{1}{3} m L + 40 m s$ --- (Equation $2$)Equating Equation $1$ and Equation $2$:$\frac{2}{3} m L = \frac{1}{3} m L + 40 m s$$\frac{1}{3} m L = 40 m s$$\frac{L}{s} = 40 	imes 3 = 120$Thus, the ratio of the latent heat of fusion to the specific heat of the liquid is $120$.

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